4q^-1/2+.25q=2q^-1/2+.5q

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Solution for 4q^-1/2+.25q=2q^-1/2+.5q equation:



4q^-1/2+.25q=2q^-1/2+.5q
We move all terms to the left:
4q^-1/2+.25q-(2q^-1/2+.5q)=0
Domain of the equation: 2+.5q)!=0
We move all terms containing q to the left, all other terms to the right
.5q)!=-2
q!=-2/1
q!=-2
q∈R
We add all the numbers together, and all the variables
4.25q-(2q^-1/2+.5q)-1/2=0
We get rid of parentheses
4.25q-2q^-.5q+1/2-1/2=0
We multiply all the terms by the denominator
(4.25q)*2-2q^*2-(.5q)*2+1-1=0
We add all the numbers together, and all the variables
(+4.25q)*2-2q^*2-(+.5q)*2+1-1=0
We add all the numbers together, and all the variables
(+4.25q)*2-2q^*2-(+.5q)*2=0
We multiply parentheses
8q-2q^*2-2q=0
Wy multiply elements
8q-4q-2q=0
We add all the numbers together, and all the variables
2q=0
q=0/2
q=0

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